2x^2-3x+2=3x-4

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Solution for 2x^2-3x+2=3x-4 equation: 



2x^2-3x+2=3x-4

We move all terms to the left:

2x^2-3x+2-(3x-4)=0

We get rid of parentheses

2x^2-3x-3x+4+2=0

We add all the numbers together, and all the variables

2x^2-6x+6=0

a = 2; b = -6; c = +6;
Δ = b2-4ac
Δ = -62-4·2·6
Δ = -12
Delta is less than zero, so there is no solution for the equation

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